MATH SOLVE

2 months ago

Q:
# Solve the following quadratic equation using the quadratic formula.

Accepted Solution

A:

The quadratic formula tells you the solution to

ax² +bx +c = 0

is

[tex]x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

Plugging in the values a=5, b=-8, c=5, you get

[tex]x=\frac{8 \pm \sqrt{(-8)^{2}-4\cdot 5\cdot 5}}{2\cdot 5} = \frac{8 \pm \sqrt{-36}}{10} = \frac{4 \pm 3i}{5}[/tex]

Your solution is

[tex]x=\frac{4-3i}{5},x=\frac{4+3i}{5}[/tex]

ax² +bx +c = 0

is

[tex]x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

Plugging in the values a=5, b=-8, c=5, you get

[tex]x=\frac{8 \pm \sqrt{(-8)^{2}-4\cdot 5\cdot 5}}{2\cdot 5} = \frac{8 \pm \sqrt{-36}}{10} = \frac{4 \pm 3i}{5}[/tex]

Your solution is

[tex]x=\frac{4-3i}{5},x=\frac{4+3i}{5}[/tex]