What is the equation of the line that is parallel to 8x-5y=2 and goes through the point (-5,-2)

Answer:8x - 5y = - 30Step-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )Rearrange 8x - 5y = 2 into this formSubtract 8x from both sides - 5y = - 8x + 2 ( divide all terms by - 5 )y = [tex]\frac{8}{5}[/tex] x - [tex]\frac{2}{5}[/tex] ← in slope- intercept formwith slope m = [tex]\frac{8}{5}[/tex]• Parallel lines have equal slopes, hencey = [tex]\frac{8}{5}[/tex] x + c ← is the partial equation of the parallel lineTo find c substitute (- 5, - 2) into the partial equation- 2 = - 8 + c ⇒ c = - 2 + 8 = 6y = [tex]\frac{8}{5}[/tex] x + 6 ← in slope- intercept formMultiply through by 55y = 8x + 30 ( subtract 5y from both sides )0 = 8x - 5y + 30 ( subtract 30 from both sides )8x - 5y = - 30 ← in standard form